$A$ and $B$ are formed when borax is dissolved in water. $C$ and $B$ are formed when borax is reacted with aqueous $HCl$ solution. What are $A$ and $C$ respectively?
- A$NaCl, NaOH$
- B$NaOH, NaCl$
- C$NaBO_2, NaCl$
- D$NaOH, NaBO_2$
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Boron halides behave as Lewis acids because of their nature.
Which one of the following elements does not form triiodide on reacting with iodine?
Match List-$I$ with List-$II$:
List-$I$ List-$II$ $a$. Borax $i$. $NaBO_2$ $b$. Kernite $ii$. $Na_2B_4O_7 \cdot 4H_2O$ $c$. Orthoboric acid $iii$. $H_3BO_3$ $d$. Borax bead $iv$. $Na_2B_4O_7 \cdot 10H_2O$
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $a$. Borax | $i$. $NaBO_2$ |
| $b$. Kernite | $ii$. $Na_2B_4O_7 \cdot 4H_2O$ |
| $c$. Orthoboric acid | $iii$. $H_3BO_3$ |
| $d$. Borax bead | $iv$. $Na_2B_4O_7 \cdot 10H_2O$ |
Choose the correct answer from the options given below:
MediumNEET 2022
View SolutionGive the increasing order of group $13$ elements for atomic radius.
Easy
View SolutionStatement $I$: Boron does not exhibit allotropy.
Statement $II$: Boron is an extremely hard and black-coloured solid.
Statement $II$: Boron is an extremely hard and black-coloured solid.
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