A boy standing on a moving truck throws a pro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The velocity of the truck is $v = 30 \,m/s$. The time taken by the truck to travel a distance of $100 \,m$ is given by $t = \frac{d}{v} = \frac{10

Vedclass · Accepted Answer

$\frac{50}{3} \,m/s$

Vedclass · Answer

(C) The velocity of the truck is $v = 30 \,m/s$. The time taken by the truck to travel a distance of $100 \,m$ is given by $t = \frac{d}{v} = \frac{100}{30} = \frac{10}{3} \,s$.Since the boy catches the projectile after this time, the total time of flight of the projectile is $T = \frac{10}{3} \,s$.For a projectile thrown vertically relative to the truck, the time of flight is given by $T = \frac{2u_y}{g}$, where $u_y$ is the vertical component of the velocity.Substituting the values: $\frac{10}{3} = \frac{2u_y}{10}$.Solving for $u_y$: $u_y = \frac{10 	imes 10}{3 	imes 2} = \frac{100}{6} = \frac{50}{3} \,m/s$.Since the projectile is thrown relative to the truck, the horizontal component of velocity relative to the truck is $0$. Thus, the speed relative to the truck is simply $u_y = \frac{50}{3} \,m/s$.

Similar Questions

$A$ particle having kinetic energy $K$ is projected at $60^{\circ}$ with the horizontal. The kinetic energy at the highest point is

$A$ projectile is fired from level ground at an angle $\theta$ above the horizontal. The elevation angle $\phi$ of the highest point as seen from the launch point is related to $\theta$ by the relation

Vedclass Test Series

Exam Paper Generator

Online Exam Module