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(A) Given: Initial velocity $u = 0 \ m \ s^{-1}$,Final velocity $v = 10 \ m \ s^{-1}$,Time $t = 2 \ s$.For constant acceleration,we use the first equa

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$5 \ m \ s^{-2}$ and $10 \ m$

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(A) Given: Initial velocity $u = 0 \ m \ s^{-1}$,Final velocity $v = 10 \ m \ s^{-1}$,Time $t = 2 \ s$.For constant acceleration,we use the first equation of motion:$v = u + at$$10 = 0 + a 	imes 2$$a = \frac{10}{2} = 5 \ m \ s^{-2}$.Now,for the distance travelled $(s)$,we use the second equation of motion:$s = ut + \frac{1}{2}at^2$$s = 0 	imes 2 + \frac{1}{2} 	imes 5 	imes (2)^2$$s = 0 + \frac{1}{2} 	imes 5 	imes 4$$s = 10 \ m$.Thus,the acceleration is $5 \ m \ s^{-2}$ and the distance travelled is $10 \ m$.

$A$ body starts from rest and acquires a velocity of $10 \ m \ s^{-1}$ in $2 \ s$. What is the acceleration of the body and the distance travelled?

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