A body is falling freely from the top of a to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Height of tower $h = 125 \ m$,initial velocity $u = 0$,acceleration $g = 10 \ m/s^2$.First,calculate the total time $t$ taken to reach the

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(B) Given: Height of tower $h = 125 \ m$,initial velocity $u = 0$,acceleration $g = 10 \ m/s^2$.First,calculate the total time $t$ taken to reach the ground using $h = ut + \frac{1}{2}gt^2$:$125 = 0 + \frac{1}{2} 	imes 10 	imes t^2$$125 = 5t^2 \Rightarrow t^2 = 25 \Rightarrow t = 5 \ s$.The distance covered in the last second is the distance covered in the total time minus the distance covered in $(t-1)$ seconds.Distance covered in $(5-1) = 4 \ s$ is $h' = \frac{1}{2} 	imes 10 	imes (4)^2 = 5 	imes 16 = 80 \ m$.Distance covered in the last second $= 125 - 80 = 45 \ m$.According to the problem,this distance is $x \%$ of the total height:$45 = \frac{x}{100} 	imes 125$$x = \frac{45 	imes 100}{125} = \frac{4500}{125} = 36$.

$A$ body is falling freely from the top of a tower of height $125 \ m$. The distance covered by the body during the last second of its motion is $x \%$ of the height of the tower. Then $x$ is (Acceleration due to gravity $= 10 \ m/s^2$)

Similar Questions

What is free fall? Write the equations of uniformly accelerated motion for an object falling freely.

$A$ body starts to fall freely under gravity. The distances covered by it in the first,second,and third seconds are in the ratio:

$A$ stone is dropped from a certain height and reaches the ground in $5 \ s$. It is stopped after $3 \ s$ of its fall and then released again. The total time taken by the stone to reach the ground will be .... $s$

$A$ ball of mass $0.5 \; kg$ is dropped from a height of $10 \; m$. The height from the ground,at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity,is $\dots \; m$. (Use $g = 10 \; m/s^2$).

$A$ ball is dropped from a height $H$ from rest. The ball travels $\frac{H}{2}$ in the last $1.0 \ s$. The total time taken by the ball to hit the ground is: (in $s$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module