$A$ big liquid drop splits into $n$ similar small drops under isothermal conditions,then in this process

The radius of one soap bubble is four times that of another. What is the ratio of the excess pressure inside the two bubbles?

The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble. The volume of the first bubble is $n$ times the volume of the second,where $n$ is:

Two bubbles $A$ and $B$ $(r_A > r_B)$ are joined through a narrow tube. Then

The diameter of a rain-drop is $0.02 \, cm$. If the surface tension of water is $72 \times 10^{-3} \, N/m$,then the pressure difference between the internal and external surfaces of the drop will be:

If two glass plates have water between them and are separated by a very small distance (see figure),it is very difficult to pull them apart. This is because the water in between forms a cylindrical surface on the side that gives rise to a lower pressure in the water in comparison to the atmosphere. If the radius of the cylindrical surface is $R$ and the surface tension of water is $T$,then the pressure in the water between the plates is lower by: