$E(1,0,0), F(0,2,0), G(0,0,3)$ are respectively the mid-points of the sides $AB, BC, CA$ of $\triangle ABC$. If $a_1, b_1, c_1$ and $a_2, b_2, c_2$ are respectively the direction ratios of $AF$ and $BG$,then $\frac{a_1^2+b_1^2+c_1^2}{a_2^2+b_2^2+c_2^2}=$

  • A
    $\frac{26}{41}$
  • B
    $\frac{13}{26}$
  • C
    $\frac{17}{43}$
  • D
    $\frac{13}{43}$

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