$A$ particle of mass $m$ and charge $Q$ moving with a speed $v$ in a circular path of radius $R$ has a magnetic moment $\mu$. If the mass of the particle is doubled and it maintains the same speed while revolving in the same circular path,then the magnetic moment will be

$A$ wire carrying current $I$ is bent in the shape $A, B, C, D, E, F, A$ as shown,where rectangle $A, B, C, D, A$ and $A, D, E, F, A$ are perpendicular to each other. If the sides of the rectangles are of lengths $a$ and $b$,then the magnitude and direction of the magnetic moment of the loop $A, B, C, D, E, F, A$ is

Two thick wires and two thin wires,all of the same material and same length,form a square in three different ways $P, Q,$ and $R$ as shown in the figure with the current connection indicated. The magnetic field at the centre of the square is zero in cases:

$A$ square loop of side $l$ is placed in the neighbourhood of an infinitely long straight wire carrying a current $I_1$. The loop carries a current $I_2$ as shown in the figure.

$A$ charged particle (charge $= q$; mass $= m$) is rotating in a circle of radius $R$ with uniform speed $V$. The ratio of its magnetic moment $(\mu)$ to the angular momentum $(L)$ is:

Write the formula for the magnetic field due to a current-carrying loop acting as a magnetic dipole at a point on its axis,and compare it with the formula for the electric field of an electric dipole.