$A$ steady current $I$ flows through a wire with one end at $O$ and the other end extending up to infinity as shown in the figure. The magnetic field at a point $P$,located at a distance $d$ from $O$,is

  • A
    $\frac{\mu_0 I}{4 \pi d \cos \alpha}(1-\sin \alpha)$
  • B
    $\frac{\mu_0 I}{2 \pi d \cos \alpha}(1-\sin \alpha)$
  • C
    $\frac{\mu_0 I}{4 \pi d}$
  • D
    $\frac{\mu_0 I}{4 \pi d \sin \alpha}(1-\cos \alpha)$

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Similar Questions

$A$ current-carrying wire in its neighborhood produces:

The magnetic field at the origin due to a current element $i \, d\vec{l}$ placed at position $\vec{r}$ is given by the Biot-Savart Law. Which of the following expressions correctly represent this magnetic field?
$(i) \, \left( \frac{\mu_0 i}{4\pi} \right) \left( \frac{d\vec{l} \times \vec{r}}{r^3} \right)$
$(ii) \, - \left( \frac{\mu_0 i}{4\pi} \right) \left( \frac{d\vec{l} \times \vec{r}}{r^3} \right)$
$(iii) \, \left( \frac{\mu_0 i}{4\pi} \right) \left( \frac{\vec{r} \times d\vec{l}}{r^3} \right)$
$(iv) \, - \left( \frac{\mu_0 i}{4\pi} \right) \left( \frac{\vec{r} \times d\vec{l}}{r^3} \right)$

As shown in the figure,two infinitely long,identical wires are bent by $90^{\circ}$ and placed in such a way that the segments $LP$ and $QM$ are along the $x-$ axis,while segments $PS$ and $QN$ are parallel to the $y-$ axis. If $OP = OQ = 4\, cm$,the magnitude of the magnetic field at $O$ is $10^{-4}\, T$,and the two wires carry equal current $i$ (see figure),find the magnitude of the current in each wire and the direction of the magnetic field at $O$. $(\mu_0 = 4\pi \times 10^{-7}\, NA^{-2})$

An arc of a circle of radius $R$ subtends an angle $\frac{\pi}{2}$ at the centre. It carries a current $i$. The magnetic field at the centre will be

For the adjoining figure,the magnetic field at point $P$ will be:

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