$\int \frac{1}{x^m \sqrt[m]{x^m+1}} d x=$

  • A
    $\frac{1}{m-1}\left(\frac{\sqrt[m]{x^m+1}}{x}\right)^m+c$
  • B
    $\frac{-1}{m-1}\left(\frac{\sqrt[m]{x^m+1}}{x}\right)^{m-1}+c$
  • C
    $\frac{-1}{m}\left(\frac{\sqrt[m]{x^m+1}}{x}\right)^m+c$
  • D
    $\frac{1}{m}\left(\frac{\sqrt[m-1]{x^m+1}}{x}\right)^m+c$

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