$A$ man of $5 \text{ feet}$ height is walking away from a light fixed at a height of $15 \text{ feet}$ at the rate of $K \text{ miles/hour}$. If the rate of increase of his shadow is $\frac{11}{5} \text{ feet/sec}$,then $K=$ (Take $1 \text{ mile} = 5280 \text{ feet}$)

  • A
    $2$
  • B
    $3$
  • C
    $4$
  • D
    $5$

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