A 1 text{ N} pendulum bob is held at an angle | vedclass

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(C) The pendulum bob is in equilibrium under the action of three forces: the tension $T$ in the string,the horizontal force $F = 2 	ext{ N}$,and the

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$\sqrt{5}$

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(C) The pendulum bob is in equilibrium under the action of three forces: the tension $T$ in the string,the horizontal force $F = 2 	ext{ N}$,and the weight $W = 1 	ext{ N}$ acting vertically downwards.Resolving the tension $T$ into horizontal and vertical components:Horizontal component: $T \sin 	heta = F = 2 	ext{ N}$Vertical component: $T \cos 	heta = W = 1 	ext{ N}$Squaring and adding both equations:$(T \sin 	heta)^2 + (T \cos 	heta)^2 = F^2 + W^2$$T^2 (\sin^2 	heta + \cos^2 	heta) = F^2 + W^2$$T^2 = F^2 + W^2$$T = \sqrt{F^2 + W^2} = \sqrt{2^2 + 1^2} = \sqrt{4 + 1} = \sqrt{5} 	ext{ N}$

$A$ $1 \text{ N}$ pendulum bob is held at an angle $\theta$ from the vertical by a $2 \text{ N}$ horizontal force $F$ as shown in the figure. The tension in the string supporting the pendulum bob (in newton) is

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