$A(3, 2, -1), B(4, 1, 0), C(2, 1, 4)$ are the vertices of a triangle $ABC$. If the bisector of $\angle BAC$ intersects the side $BC$ at $D(p, q, r)$,then $\sqrt{2p + q + r} =$

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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