C_3H_6 xrightarrow{X} Y xrightarrow[C_6H_6]{A | vedclass

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(C) $1$. The reaction begins with propene $(C_3H_6)$.$2$. The reagent $X$ is $HBr/ROOR$ (peroxide effect/anti-Markovnikov addition),which converts pro

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$HBr/ROOR$,isopropylbenzene

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(C) $1$. The reaction begins with propene $(C_3H_6)$.$2$. The reagent $X$ is $HBr/ROOR$ (peroxide effect/anti-Markovnikov addition),which converts propene to $1$-bromopropane $(Y = CH_3CH_2CH_2Br)$.$3$. In the presence of $AlCl_3$,$1$-bromopropane undergoes rearrangement to form a more stable isopropyl carbocation $(CH_3CH^+CH_3)$.$4$. This isopropyl carbocation then undergoes Friedel-Crafts alkylation with benzene $(C_6H_6)$ to form isopropylbenzene (cumene) as the major product $(Z)$.$5$. Thus,$X$ is $HBr/ROOR$ and $Z$ is isopropylbenzene.

$C_3H_6$ $\xrightarrow{X} Y$ $\xrightarrow[C_6H_6]{AlCl_3} Z \text{ (major product)}$
$X$ and $Z$ respectively in the following reaction sequence are

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$C_3H_6$ $\xrightarrow{X} Y$ $\xrightarrow[C_6H_6]{AlCl_3} Z \text{ (major product)}$$X$ and $Z$ respectively in the following reaction sequence are