A halogen compound X (C_4 H_9 Br) on hydrolys | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction sequence is as follows:$1$. Hydrolysis of $C_4 H_9 Br$ $(X)$ gives an alcohol $Y$ $(C_4 H_9 OH)$.$2$. The alcohol $Y$ undergoes dehyd

Vedclass · Accepted Answer

$(CH_3)_3 CBr$

Vedclass · Answer

(A) The reaction sequence is as follows:$1$. Hydrolysis of $C_4 H_9 Br$ $(X)$ gives an alcohol $Y$ $(C_4 H_9 OH)$.$2$. The alcohol $Y$ undergoes dehydration with $20 \% H_3 PO_4$ at $358 \ K$ to form an alkene.$3$. Tertiary butyl bromide,$(CH_3)_3 CBr$,on hydrolysis gives tertiary butyl alcohol,$(CH_3)_3 COH$.$4$. Tertiary butyl alcohol undergoes easy dehydration with $20 \% H_3 PO_4$ at $358 \ K$ to form isobutylene ($2$-methylpropene),which is consistent with the provided reaction conditions.$5$. Therefore,$X$ is $(CH_3)_3 CBr$.

$A$ halogen compound $X$ $(C_4 H_9 Br)$ on hydrolysis gives an alcohol $Y$. The alcohol $Y$ undergoes dehydration with $20 \% H_3 PO_4$ at $358 \ K$. What is $X$?

Similar Questions

Which one of the following is more readily hydrolysed by $S_{N}1$ mechanism?

Which of the following will have an enantiomer?

$A$ solution of $(-)-1-$chloro$-1-$phenylethane in toluene racemises slowly in the presence of a small amount of $SbCl_5$,due to the formation of:

Number of moles of $CH_3MgBr$ consumed in the above reaction is:

If all the nucleophilic substitution reactions at saturated carbon atoms in the above sequence of reactions follow $S_N2$ mechanism,then $\underline{E}$ and $\underline{E}$ will be respectively,

Vedclass Test Series

Exam Paper Generator

Online Exam Module