(B) Given,length of the arc $l = 44 \text{ cm}$.Radius of the circle $r = 12 \text{ cm}$.The angle $\theta$ subtended by the arc at the centre in radi

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$\left(\frac{660}{\pi}\right)^{\circ}$

(B) Given,length of the arc $l = 44 \text{ cm}$.Radius of the circle $r = 12 \text{ cm}$.The angle $\theta$ subtended by the arc at the centre in radians is given by $\theta = \frac{l}{r}$.$\theta = \frac{44}{12} = \frac{11}{3} \text{ radians}$.To convert the angle from radians to degrees,we multiply by $\frac{180}{\pi}$.$\theta_{\text{deg}} = \frac{11}{3} \times \frac{180}{\pi} = \frac{11 \times 60}{\pi} = \left(\frac{660}{\pi}\right)^{\circ}$.

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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$A$ wire of length $44 \text{ cm}$ is bent into an arc of a circle of radius $12 \text{ cm}$. The angle (in degrees) subtended by the arc at the centre of the circle is

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A
$\left(\frac{11}{3}\right)^{\circ}$
B
$\left(\frac{660}{\pi}\right)^{\circ}$
C
$150^{\circ}$
D
$\left(\frac{5}{3}\right)^{\circ}$

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Class 11

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Trigonometrical Ratios, Functions and Identities

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Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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TS EAMCET 2019 Paper All TS EAMCET years →

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$A$ wire of length $44 \text{ cm}$ is bent into an arc of a circle of radius $12 \text{ cm}$. The angle (in degrees) subtended by the arc at the centre of the circle is

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