Easy
$\alpha$ and $\beta$ are the roots of $x^2+2x+c=0$. If $\alpha^3+\beta^3=4$,then the value of $c$ is
- A-$2$
- B$3$
- C$2$
- D$4$
Explore More
Similar Questions
If $\alpha, \beta, \gamma$ are the roots of the equation $x^3-6x^2+11x-6=0$,then $\sum \alpha^2 \beta + \sum \alpha \beta^2 =$
If $\alpha$ and $\beta$ are the roots of $x^{2}-ax+b^{2}=0$,then $\alpha^{2}+\beta^{2}$ is equal to
MediumKCET 2015
View SolutionIf $\alpha, \beta, \gamma$ are the roots of the equation $x^3-3x^2+3x+1=0$,then $\alpha^2\beta^2+\beta^2\gamma^2+\gamma^2\alpha^2=$
If the roots of the equation $x^2 + px + q = 0$ differ by $1$,then:
Easy
View Solution$\alpha, \beta, \gamma$ are the roots of the equation $x^3-10 x^2+7 x+8=0$. Match the following and choose the correct answer.
$A. \alpha + \beta + \gamma$ $(1) -\frac{43}{4}$ $B. \alpha^2 + \beta^2 + \gamma^2$ $(2) -\frac{7}{8}$ $C. \frac{1}{\alpha} + \frac{1}{\beta} + \frac{1}{\gamma}$ $(3) 86$ $D. \frac{\alpha}{\beta \gamma} + \frac{\beta}{\gamma \alpha} + \frac{\gamma}{\alpha \beta}$ $(4) 0$ $(5) 10$
| $A. \alpha + \beta + \gamma$ | $(1) -\frac{43}{4}$ |
| $B. \alpha^2 + \beta^2 + \gamma^2$ | $(2) -\frac{7}{8}$ |
| $C. \frac{1}{\alpha} + \frac{1}{\beta} + \frac{1}{\gamma}$ | $(3) 86$ |
| $D. \frac{\alpha}{\beta \gamma} + \frac{\beta}{\gamma \alpha} + \frac{\gamma}{\alpha \beta}$ | $(4) 0$ |
| $(5) 10$ |
DifficultAP EAMCET 2004
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo