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(D) Given: Carrier frequency $f_c = 5 MHz$,carrier peak voltage $V_c = 40 V$,modulation index $\mu = 0.75$.$1$. Calculation of message signal peak vol

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$30 V ; 20 kHz$

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(D) Given: Carrier frequency $f_c = 5 MHz$,carrier peak voltage $V_c = 40 V$,modulation index $\mu = 0.75$.$1$. Calculation of message signal peak voltage $(V_m)$:The modulation index is defined as $\mu = \frac{V_m}{V_c}$.Substituting the values: $0.75 = \frac{V_m}{40 V}$.$V_m = 40 V 	imes 0.75 = 30 V$.$2$. Calculation of message signal frequency $(f_m)$:The frequency separation between the two side-bands (upper side-band and lower side-band) is equal to the bandwidth,which is $2 f_m$.Given: $2 f_m = 40 kHz$.$f_m = \frac{40 kHz}{2} = 20 kHz$.Therefore,the peak voltage and frequency of the message signal are $30 V$ and $20 kHz$ respectively.

$A$ message signal is used to modulate a carrier signal of frequency $5 MHz$ and peak voltage of $40 V$. In the process,two side-bands are produced separated by $40 kHz$. If the modulation index is $0.75$,then the peak voltage and frequency of the message signal,respectively,are:

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