A carrier wave of peak voltage 10 ,V is used | vedclass

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(A) The modulation index $m$ is defined as the ratio of the peak voltage of the modulating signal $(A_m)$ to the peak voltage of the carrier wave $(A_

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$8$

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(A) The modulation index $m$ is defined as the ratio of the peak voltage of the modulating signal $(A_m)$ to the peak voltage of the carrier wave $(A_c)$.Given:Carrier wave peak voltage,$A_c = 10 \,V$Modulation index,$m = 80 \% = 0.8$Formula:$m = \frac{A_m}{A_c}$Substituting the values:$0.8 = \frac{A_m}{10 \,V}$$A_m = 0.8 	imes 10 \,V = 8 \,V$Therefore,the peak voltage of the modulating signal should be $8 \,V$.

$A$ carrier wave of peak voltage $10 \,V$ is used to transmit a message signal. What should be the peak voltage of the modulating signal in order to have a modulation index of $80 \%$ (in $\,V$)?

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