A rifle of 20 ~kg mass can fire 4 bullets per | vedclass

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(D) The force exerted by the bullets on the rifle is equal to the rate of change of momentum of the bullets.Given:Mass of rifle,$M = 20 ~kg$Number of

Vedclass · Accepted Answer

$56$

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(D) The force exerted by the bullets on the rifle is equal to the rate of change of momentum of the bullets.Given:Mass of rifle,$M = 20 ~kg$Number of bullets per second,$n = 4$Mass of each bullet,$m = 35 	imes 10^{-3} ~kg$Velocity of each bullet,$v = 400 ~ms^{-1}$The force exerted by the bullets on the rifle (recoil force) is given by:$F_{recoil} = n 	imes (m 	imes v)$$F_{recoil} = 4 	imes (35 	imes 10^{-3} ~kg) 	imes (400 ~ms^{-1})$$F_{recoil} = 4 	imes 35 	imes 0.4 = 56 ~N$To prevent the rifle from moving backwards,an equal and opposite force must be applied on the rifle.Therefore,the required force is $56 ~N$ in the forward direction.

$A$ rifle of $20 ~kg$ mass can fire $4$ bullets per second. The mass of each bullet is $35 \times 10^{-3} ~kg$ and its final velocity is $400 ~ms^{-1}$. What force must be applied on the rifle so that it does not move backwards while firing the bullets (in $~N$)?

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