CH_3CH_2COOH xrightarrow{P_2O_5} X xrightarro | vedclass

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(B) $1$. The reaction of propanoic acid $(CH_3CH_2COOH)$ with $P_2O_5$ (a dehydrating agent) leads to the formation of propanoic anhydride,which is $X

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$X$$Y$$Z$$(CH_3CH_2CO)_2O$$CH_3CH_2CO_2H$$CH_3CH_2COCl$

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(B) $1$. The reaction of propanoic acid $(CH_3CH_2COOH)$ with $P_2O_5$ (a dehydrating agent) leads to the formation of propanoic anhydride,which is $X = (CH_3CH_2CO)_2O$.$2$. The hydrolysis of propanoic anhydride $(X)$ with $H_2O$ regenerates propanoic acid,which is $Y = CH_3CH_2COOH$.$3$. The reaction of propanoic acid $(Y)$ with $SOCl_2$ (thionyl chloride) converts the carboxylic acid group into an acid chloride,resulting in propanoyl chloride,which is $Z = CH_3CH_2COCl$.$4$. Therefore,the correct sequence is $X = (CH_3CH_2CO)_2O$,$Y = CH_3CH_2COOH$,and $Z = CH_3CH_2COCl$.

$CH_3CH_2COOH$ $\xrightarrow{P_2O_5}$ $X$ $\xrightarrow{H_2O}$ $Y$ $\xrightarrow{SOCl_2}$ $Z$
Identify $X$,$Y$ and $Z$.

Similar Questions

Arrange the following compounds in the correct order of their boiling points:
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$CH_3CH_2COOH$ $\xrightarrow{P_2O_5}$ $X$ $\xrightarrow{H_2O}$ $Y$ $\xrightarrow{SOCl_2}$ $Z$Identify $X$,$Y$ and $Z$.