A gas does 4.5 ,J of external work during adi | vedclass

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(B) From the first law of thermodynamics, we have the equation $dQ = dU + dW$. In an adiabatic process, there is no exchange of heat with the surround

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decreased by $4.5 \,J$

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(B) From the first law of thermodynamics, we have the equation $dQ = dU + dW$. In an adiabatic process, there is no exchange of heat with the surroundings, so $dQ = 0$. Substituting this into the equation, we get $0 = dU + dW$, which implies $dU = -dW$. Given that the gas does $4.5 \,J$ of external work, $dW = 4.5 \,J$. Therefore, $dU = -4.5 \,J$. Since the change in internal energy $dU$ is negative, the internal energy decreases by $4.5 \,J$.

$A$ gas does $4.5 \,J$ of external work during adiabatic expansion. If its temperature falls by $2 \,K$, then its internal energy will be

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