$A$ hammer of mass $200 \ kg$ strikes a steel block of mass $200 \ g$ with a velocity $8 \ ms^{-1}$. If $23 \%$ of the energy is utilized to heat the steel block,the rise in temperature of the block is (specific heat capacity of steel,$s = 460 \ J \ kg^{-1} \ K^{-1}$) (in $K$)

The heat energy required to convert $10 \,kg$ of ice at $-10^{\circ} C$ into water at $0^{\circ} C$ is (specific heat capacity of ice $=0.5 \,cal \,g^{-1} \,^{\circ}C^{-1}$ and latent heat of fusion of ice $=80 \,cal \,g^{-1}$)

Match the following List-$I$ with List-$II$.

List-$I$	List-$II$
$A$. When ice melts into water	$I$. Volume increases
$B$. When water changes into steam	$II$. Volume decreases
$C$. Melting point of ice	$III$. Increases with increase of pressure
$D$. Boiling point of water	$IV$. Decreases with increase in pressure

$A$ given mass $m$ of a hypothetical solid is supplied with heat continuously at a constant rate and the graph shown in the figure is plotted. If $L_f$ and $L_v$ are latent heats of fusion and vaporization,and $S_l$ and $S_s$ are specific heats of liquid and solid respectively,it can be concluded that:

When the pressure on water is increased,the boiling temperature of water as compared to $100^{\circ}C$ will be:

Heat needed to convert $1 \ kg$ of ice at $0^{\circ} C$ to steam at $100^{\circ} C$ is