A photon of wavelength 3000 mathring{A} stri | vedclass

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(C) Given: Wavelength $\lambda = 3000 \ \mathring{A} = 3000 	imes 10^{-10} \ m = 3 	imes 10^{-7} \ m$. Work function $\phi = 2.13 \ eV$. Using Einst

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(C) Given: Wavelength $\lambda = 3000 \ \mathring{A} = 3000 	imes 10^{-10} \ m = 3 	imes 10^{-7} \ m$. Work function $\phi = 2.13 \ eV$. Using Einstein's photoelectric equation: $K.E. = E - \phi = \frac{hc}{\lambda} - \phi$. Energy of photon $E = \frac{hc}{\lambda} = \frac{6.626 	imes 10^{-34} \ J \ s 	imes 3 	imes 10^8 \ m/s}{3 	imes 10^{-7} \ m} = 6.626 	imes 10^{-19} \ J$. Converting $E$ to $eV$: $E = \frac{6.626 	imes 10^{-19} \ J}{1.602 	imes 10^{-19} \ J/eV} \approx 4.136 \ eV$. Kinetic Energy $K.E. = 4.136 \ eV - 2.13 \ eV = 2.006 \ eV \approx 2.0 \ eV$.

$A$ photon of wavelength $3000 \ \mathring{A}$ strikes a metal surface. The work function of the metal is $2.13 \ eV$. What is the kinetic energy of the emitted photoelectron (in $eV$)? $\left(h=6.626 \times 10^{-34} \ J \ s\right)$

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