a,b,c,d are electromagnetic radiations. Frequ | vedclass

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Question

(A) The energy of electromagnetic radiation is given by $E = h
u = \frac{hc}{\lambda}$.For $a$: $
u_a = 3 	imes 10^{15} \ Hz$.For $b$: $
u_b = 2 \

Vedclass · Accepted Answer

$b < d < c < a$

Vedclass · Answer

(A) The energy of electromagnetic radiation is given by $E = h
u = \frac{hc}{\lambda}$.For $a$: $
u_a = 3 	imes 10^{15} \ Hz$.For $b$: $
u_b = 2 	imes 10^{14} \ Hz$.For $c$: $\lambda_c = 400 \ nm = 400 	imes 10^{-9} \ m$. Frequency $
u_c = \frac{c}{\lambda_c} = \frac{3 	imes 10^8}{400 	imes 10^{-9}} = 7.5 	imes 10^{14} \ Hz$.For $d$: $\lambda_d = 750 \ nm = 750 	imes 10^{-9} \ m$. Frequency $
u_d = \frac{c}{\lambda_d} = \frac{3 	imes 10^8}{750 	imes 10^{-9}} = 4 	imes 10^{14} \ Hz$.Comparing frequencies: $
u_b (2 	imes 10^{14}) Since $E \propto 
u$,the increasing order of energies is $b < d < c < a$.

$a$,$b$,$c$,$d$ are electromagnetic radiations. Frequencies of $a$,$b$ are $3 \times 10^{15} \ Hz$,$2 \times 10^{14} \ Hz$,respectively,whereas wavelengths of $c$,$d$ are $400 \ nm$,$750 \ nm$,respectively. The increasing order of their energies is

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