(D) Given that $3.011 \times 10^{22}$ atoms of an element weigh $1.15 \ g$. We know that $1 \ mol$ of an element contains $N_A$ atoms,where $N_A \appr

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(D) Given that $3.011 \times 10^{22}$ atoms of an element weigh $1.15 \ g$. We know that $1 \ mol$ of an element contains $N_A$ atoms,where $N_A \approx 6.022 \times 10^{23} \ atoms/mol$. Mass of $6.022 \times 10^{23}$ atoms (molar mass) $= \frac{1.15 \ g}{3.011 \times 10^{22} \ atoms} \times 6.022 \times 10^{23} \ atoms/mol$. $= 1.15 \times 20 = 23 \ g/mol$. Therefore,the atomic mass of the element is $23 \ amu$.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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$3.011 \times 10^{22}$ atoms of an element weigh $1.15 \ g$. The atomic mass of the element is: (in $amu$)

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A
$10$
B
$2.3$
C
$35.5$
D
$23$

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Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

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$3.011 \times 10^{22}$ atoms of an element weigh $1.15 \ g$. The atomic mass of the element is: (in $amu$)

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