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(D) In a hexagonal close-packed $(HCP)$ structure,the number of oxide ions per unit cell is $6$.The number of octahedral voids in an $HCP$ structure i

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$M_2O_3$

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(D) In a hexagonal close-packed $(HCP)$ structure,the number of oxide ions per unit cell is $6$.The number of octahedral voids in an $HCP$ structure is equal to the number of atoms,which is $6$.Given that two out of every three octahedral holes are occupied by metal ions,the number of metal ions $= \frac{2}{3} 	imes 6 = 4$.The ratio of metal ions to oxide ions is $4 : 6$,which simplifies to $2 : 3$.Therefore,the formula of the metal oxide is $M_2O_3$.

$A$ metal oxide crystallises in a hexagonal close-packed $(HCP)$ array of oxide ions with two out of every three octahedral holes occupied by metal ions. The formula of the metal oxide is:

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