$A$ compound is formed by two elements $A$ and $B$. Atoms of the element $B$ (as anion) make $ccp$ lattice and those of element $A$ (as cation) occupy all tetrahedral voids. The formula of the compound is
- A$A_4 B_3$
- B$AB$
- C$AB_2$
- D$A_2 B$
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Similar Questions
Find the void volume of a $bcc$ unit cell in $cm^3$ if the volume of the unit cell is $1.5 \times 10^{-22} \ cm^3$.
If the anion $(A)$ forms a hexagonal closest packing and the cation $(C)$ occupies only $2/3$ of the octahedral voids in it,then the general formula of the compound is :-
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View SolutionCalculate the volume occupied by all atoms in a $bcc$ unit cell if the volume of the unit cell is $1.5 \times 10^{-22} \ cm^3$.
The total number of octahedral void$(s)$ per atom present in a cubic close packed structure is
Which of the following metals crystallizes in a cubic closest packing $(CCP)$ structure?
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