$Xe_{(g)}$ and $F_{2(g)}$ react in the ratio $1:20$ at $573 \ K$ and $60-70 \ bar$ to form $A$. When $A$ is completely hydrolyzed,$B$ and $HF$ are formed. $A$ and $B$ are respectively:
- A$XeF_2, O_2$
- B$XeF_6, XeO_3$
- C$XeF_4, XeOF_4$
- D$XeF_4, XeO_2 F_2$
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Similar Questions
At $143 \ K$,the reaction of $XeF_4$ with $O_2F_2$ produces a xenon compound $Y$. The total number of lone pair$(s)$ of electrons present on the whole molecule of $Y$ is . . . . .
Match the compounds of $Xe$ in Column-$I$ with the molecular structure in Column-$II$.
Column-$I$ Column-$II$ $(a)$ $XeF_2$ $(i)$ Square planar $(b)$ $XeF_4$ $(ii)$ Linear $(c)$ $XeO_3$ $(iii)$ Square pyramidal $(d)$ $XeOF_4$ $(iv)$ Pyramidal
| Column-$I$ | Column-$II$ |
|---|---|
| $(a)$ $XeF_2$ | $(i)$ Square planar |
| $(b)$ $XeF_4$ | $(ii)$ Linear |
| $(c)$ $XeO_3$ | $(iii)$ Square pyramidal |
| $(d)$ $XeOF_4$ | $(iv)$ Pyramidal |
MediumNEET 2020
View Solution$XeF_4$ reacting strongly with water gives .......
DifficultAIIMS 2006
View SolutionWhat is the correct order of occurrence (\% by weight) in air of $Ne, Ar$ and $Kr$?
$XeF_{6}$ on partial hydrolysis gives a compound $X$,which has square pyramidal geometry. '$X$' is
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