| vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Time-period in spring-block system is given by, $T = 2 \pi \sqrt{\frac{m}{k}} $If mass is doubled, $T^{\prime} = 2 \pi \sqrt{\frac{2m}{k}} $ $ \Ri

Vedclass · Accepted Answer

$ \begin{array}{llll} 3 & 2 & 1 & 4 \end{array} $

Vedclass · Answer

(A) Time-period in spring-block system is given by, $T = 2 \pi \sqrt{\frac{m}{k}} $If mass is doubled, $T^{\prime} = 2 \pi \sqrt{\frac{2m}{k}} $ $ \Rightarrow \quad T^{\prime} = \sqrt{2} T $Hence, time period becomes $ \sqrt{2} $ times, if the mass of the block is doubled.$ (A ightarrow 4) $(B) For spring, $ \mathrm{PE} = \frac{1}{2} k x^2 $If spring constant is increased 4 times, PE becomes 4 times.$ (B ightarrow 3) $(C) Speed of the block, $ v = \omega A $Hence, velocity of the block becomes twice when amplitude of the oscillation is doubled.$ (C ightarrow 2) $(D) Energy of the oscillation, $ E = \frac{1}{2} m \omega^2 a^2 $$ \begin{aligned} & & E^{\prime} = \frac{1}{2} m \omega^{\prime 2} a^2 \ \Rightarrow & E^{\prime} & = \frac{1}{2} m(2 \omega)^2 a^2 = \frac{4}{2} m \omega^2 a^2 \quad \left( \because \omega^{\prime} = 2 \omega ight) \ \Rightarrow & E^{\prime} & = 4 E \end{aligned} $Energy of the oscillation becomes 4 times when angular frequency is doubled.$ (D ightarrow 1) $

Similar Questions

If a polygon of $n$ sides has $275$ diagonals,then $n$ is equal to

Propanal on treatment with dilute sodium hydroxide forms

$A$ transformer works on the principle of

In the concentration of $PbS$ containing $ZnS$ as impurity,the depressant used is:

$A$ horizontal force of $10\, N$ is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and the wall is $0.2$. The weight of the block is ........ $N$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module