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Question

(C) Let the original nucleus be ${ }_Z^A X$. After losing $2$ alpha particles $({ }_2^4 He)$,the new nucleus $R$ will have an atomic mass number $A' =

Vedclass · Accepted Answer

$248$

Vedclass · Answer

(C) Let the original nucleus be ${ }_Z^A X$. After losing $2$ alpha particles $({ }_2^4 He)$,the new nucleus $R$ will have an atomic mass number $A' = A - 2 	imes 4 = A - 8$.Given that the volume of the new nucleus $R$ is $60$ times the volume of an alpha particle $({ }_2^4 He)$:Volume of nucleus $\propto$ (Mass number $A$)$\Rightarrow V_R = 60 	imes V_{\alpha}$Since $V \propto A$,we have $A' = 60 	imes 4$.Substituting $A' = A - 8$:$A - 8 = 240$$A = 248$.

$A$ nucleus with atomic mass number $A$ produces another nucleus by losing $2$ alpha particles. The volume of the new nucleus is $60$ times that of the alpha particle. The atomic mass number $A$ of the original nucleus is:

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