(B) We consider the vertical motion of the ball.Initial vertical velocity: $u_y = u \sin \theta = 20 \times \sin 30^{\circ} = 20 \times \frac{1}{2} =

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(B) We consider the vertical motion of the ball.Initial vertical velocity: $u_y = u \sin \theta = 20 \times \sin 30^{\circ} = 20 \times \frac{1}{2} = 10 \,m/s$.Vertical acceleration: $a_y = -g = -10 \,m/s^2$.Time taken to reach the ground: $t = 3 \,s$.Using the equation of motion for vertical displacement: $s_y = u_y t + \frac{1}{2} a_y t^2$.Here, the displacement $s_y = -h$ (where $h$ is the height of the building).$-h = (10)(3) + \frac{1}{2}(-10)(3)^2$.$-h = 30 - 5(9) = 30 - 45 = -15 \,m$.Therefore, $h = 15 \,m$.

Class 11 Physics 3-2.Motion in Plane Projectile Motion from Hight

Easy

$A$ ball is thrown upward from the top of a building at an angle of $30^{\circ}$ to the horizontal and with an initial speed of $20 \,m/s$. If the ball strikes the ground after $3 \,s$, then the height of the building is (acceleration due to gravity $g = 10 \,m/s^2$) (in $\,m$)

AP EAMCET 2022 All AP EAMCET

A
$10$
B
$15$
C
$20$
D
$25$

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3-2.Motion in Plane

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Projectile Motion from Hight

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$A$ body is projected horizontally from a height with a speed of $20 \, m/s$. What will be its speed after $5 \, s$ (in $, m/s$)? (Take $g = 10 \, m/s^2$)

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$A$ body is projected horizontally from the top of a tower of height $180 \ m$ with a velocity of $20 \ ms^{-1}$. If acceleration due to gravity is $10 \ ms^{-2}$,then match the following:
List-$I$ (Kinematic Variable) List-$II$ (Value)
$A$. Velocity of the body after $1 \ s$ (in $ms^{-1}$) $I$. $5$
$B$. Horizontal displacement of the body after $1 \ s$ (in $m$) $II$. $20$
$C$. Vertical displacement of the body after $1 \ s$ (in $m$) $III$. $10$
$D$. Vertical velocity of the body after $1 \ s$ (in $ms^{-1}$) $IV$. $22.4$

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$A$ fighter plane is flying horizontally at an altitude of $1.5\, km$ with a speed of $720\, km/h$. At what angle of sight (with respect to the horizontal) should the pilot drop the bomb when the target is seen,in order to hit the target?

Medium

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An aeroplane moving horizontally with a speed of $180\, km/hr$ drops a food packet while flying at a height of $490\, m$. The horizontal range is........$m$.

Medium

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$A$ particle is dropped from a height of $20\,m$ above horizontal ground. Due to wind,the particle experiences a constant horizontal acceleration of $6\,m/s^2$. Find the horizontal displacement of the particle when it reaches the ground.

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List-$I$ (Kinematic Variable)	List-$II$ (Value)
$A$. Velocity of the body after $1 \ s$ (in $ms^{-1}$)	$I$. $5$
$B$. Horizontal displacement of the body after $1 \ s$ (in $m$)	$II$. $20$
$C$. Vertical displacement of the body after $1 \ s$ (in $m$)	$III$. $10$
$D$. Vertical velocity of the body after $1 \ s$ (in $ms^{-1}$)	$IV$. $22.4$

$A$ ball is thrown upward from the top of a building at an angle of $30^{\circ}$ to the horizontal and with an initial speed of $20 \,m/s$. If the ball strikes the ground after $3 \,s$, then the height of the building is (acceleration due to gravity $g = 10 \,m/s^2$) (in $\,m$)

Similar Questions

$A$ body is projected horizontally from a height with a speed of $20 \, m/s$. What will be its speed after $5 \, s$ (in $, m/s$)? (Take $g = 10 \, m/s^2$)

$A$ fighter plane is flying horizontally at an altitude of $1.5\, km$ with a speed of $720\, km/h$. At what angle of sight (with respect to the horizontal) should the pilot drop the bomb when the target is seen,in order to hit the target?

An aeroplane moving horizontally with a speed of $180\, km/hr$ drops a food packet while flying at a height of $490\, m$. The horizontal range is........$m$.

$A$ particle is dropped from a height of $20\,m$ above horizontal ground. Due to wind,the particle experiences a constant horizontal acceleration of $6\,m/s^2$. Find the horizontal displacement of the particle when it reaches the ground.

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