A body is moving with an initial velocity of | vedclass

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(A) The initial velocity of the body is $u = 10\sqrt{2} \ m/s$ in the north-east direction. Resolving this into components along the east $(\hat{i})$

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$10 \ m/s$, towards east

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(A) The initial velocity of the body is $u = 10\sqrt{2} \ m/s$ in the north-east direction. Resolving this into components along the east $(\hat{i})$ and north $(\hat{j})$ directions:$u = (10\sqrt{2} \cos 45^{\circ}) \hat{i} + (10\sqrt{2} \sin 45^{\circ}) \hat{j} = 10 \hat{i} + 10 \hat{j} \ m/s$.The acceleration is directed towards the south, so $a = -2 \hat{j} \ m/s^2$.Using the first equation of motion, $v = u + at$, for $t = 5 \ s$:$v = (10 \hat{i} + 10 \hat{j}) + (-2 \hat{j}) 	imes 5$$v = 10 \hat{i} + 10 \hat{j} - 10 \hat{j}$$v = 10 \hat{i} \ m/s$.Thus, the final velocity is $10 \ m/s$ towards the east.

$A$ body is moving with an initial velocity of $10 \sqrt{2} \ m/s$ in the north-east direction. If it is subjected to an acceleration of $2 \ m/s^2$ directed towards the south, then the velocity of the body after $5 \ s$ is:

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