$A$ material has Poisson's ratio $0.50$. If a uniform rod made of this material suffers a longitudinal strain of $2 \times 10^{-3}$,then the percentage change in volume is

$A$ tension of $20 \,N$ is applied to a copper wire of cross-sectional area $0.01 \,cm^2$. The Young's modulus of copper is $1.1 \times 10^{11} \,N/m^2$ and the Poisson's ratio is $0.32$. The decrease in the cross-sectional area of the wire is:

For silver,Young's modulus is $7.25 \times 10^{10} \ N/m^2$ and Bulk modulus is $11 \times 10^{10} \ N/m^2$. Its Poisson's ratio will be

In materials like aluminium and copper, the correct order of magnitude of various elastic moduli is:

$A$ cylindrical wire of radius $1\, mm$,length $1\, m$,Young's modulus $Y = 2 \times 10^{11}\, N/m^2$,and Poisson's ratio $\mu = \pi / 10$ is stretched by a force of $100\, N$. What will be its new radius (in $, mm$)?

$A 3 \ m$ long steel wire is stretched to increase its length by $0.3 \ cm$. Poisson's ratio for steel is $0.26$. The lateral strain produced in the wire is