$A$ bar magnet of magnetic moment $M$ and moment of inertia $I$ is freely suspended such that the magnetic axial line is in the direction of the magnetic meridian. If the magnet is displaced by a very small angle $\theta$,the angular acceleration is (Magnetic induction of earth's horizontal field $= B_H$)
- A$\frac{M B_H \theta}{I}$
- B$\frac{I B_H \theta}{M}$
- C$\frac{M \theta}{I B_H}$
- D$\frac{I \theta}{M B_H}$
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