A point charge of 10^{-7} text{ C} is situate | vedclass

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(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q}{\epsilon_0}$,where $q$ is the net ch

Vedclass · Accepted Answer

$1.13 	imes 10^4 	ext{ N} \cdot 	ext{m}^2 \cdot 	ext{C}^{-1}$

Vedclass · Answer

(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q}{\epsilon_0}$,where $q$ is the net charge enclosed by the surface and $\epsilon_0$ is the permittivity of free space.Given,$q = 10^{-7} 	ext{ C}$ and $\epsilon_0 = 8.854 	imes 10^{-12} 	ext{ C}^2 \cdot 	ext{N}^{-1} \cdot 	ext{m}^{-2}$.Substituting the values:$\phi = \frac{10^{-7}}{8.854 	imes 10^{-12}}$$\phi = \frac{1}{8.854} 	imes 10^5$$\phi \approx 0.1129 	imes 10^5 	ext{ N} \cdot 	ext{m}^2 \cdot 	ext{C}^{-1}$$\phi \approx 1.129 	imes 10^4 	ext{ N} \cdot 	ext{m}^2 \cdot 	ext{C}^{-1}$Rounding to the nearest option,we get $\phi \approx 1.13 	imes 10^4 	ext{ N} \cdot 	ext{m}^2 \cdot 	ext{C}^{-1}$.

$A$ point charge of $10^{-7} \text{ C}$ is situated at the centre of a cube of $1 \text{ m}$ side. The electric flux through its surface is

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