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(B) Given: Radius of the circular loop $r = 14 \ cm = 0.14 \ m$.Rate of change of magnetic field $\frac{dB}{dt} = 0.05 \ Ts^{-1}$.According to Faraday

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$3.08$

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(B) Given: Radius of the circular loop $r = 14 \ cm = 0.14 \ m$.Rate of change of magnetic field $\frac{dB}{dt} = 0.05 \ Ts^{-1}$.According to Faraday's law of electromagnetic induction,the magnitude of induced emf $|e|$ is given by $|e| = \frac{d\phi}{dt}$.Since the magnetic field is perpendicular to the plane,the magnetic flux $\phi = B \cdot A$.Thus,$|e| = \frac{d}{dt}(BA) = A \frac{dB}{dt}$.The area of the loop $A = \pi r^2 = \frac{22}{7} 	imes (0.14)^2 = \frac{22}{7} 	imes 0.0196 = 0.0616 \ m^2$.Substituting the values: $|e| = 0.0616 	imes 0.05 = 0.00308 \ V$.Converting to millivolts: $|e| = 3.08 	imes 10^{-3} \ V = 3.08 \ mV$.

$A$ circular loop of wire of radius $14 \ cm$ is placed in a magnetic field directed perpendicular to the plane of the loop. If the field decreases at a steady rate of $0.05 \ Ts^{-1}$ in some interval,then the magnitude of the emf induced in the loop is (in $mV$)

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