$A$ galvanometer of resistance $40 \Omega$ gives a deflection of $10 \text{ divisions per } mA$. There are $50 \text{ divisions}$ on the scale. The maximum current that can pass through the circuit when a shunt resistance of $2 \Omega$ is connected is: (in $\text{ mA}$)

  • A
    $105$
  • B
    $155$
  • C
    $210$
  • D
    $75$

Explore More

Similar Questions

What is the resistance of an ideal ammeter?

$A$ galvanometer is used in the laboratory for the null point in electrical experiments. If,on passing a current of $6 \, mA$,it produces a deflection of $2^{\circ}$,its figure of merit is close to:

The number of turns in a coil of a galvanometer is tripled. Then:

$A$ moving coil galvanometer is converted into an ammeter reading up to $0.03\,A$ by connecting a shunt of resistance $4r$ across it,and into an ammeter reading up to $0.06\,A$ when a shunt of resistance $r$ is connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used?

$A$ galvanometer of resistance $25\,\Omega$ gives full-scale deflection for a current of $10\,mA$. It is to be converted into a voltmeter of range $100\,V$ by connecting a resistance $R$ in series with the galvanometer. The value of resistance $R$ in $\Omega$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo