A battery with a 12 , V emf has an initial ch | vedclass

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(B) Given:Electromotive force (emf) $\varepsilon = 12 \, V$Total charge capacity $q = 80 \, A \cdot h$Power output $P = 120 \, W$The total energy $E$

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$8$

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(B) Given:Electromotive force (emf) $\varepsilon = 12 \, V$Total charge capacity $q = 80 \, A \cdot h$Power output $P = 120 \, W$The total energy $E$ stored in the battery is given by $E = q \cdot \varepsilon$.Substituting the values: $E = 80 \, A \cdot h 	imes 12 \, V = 960 \, W \cdot h$.Since power $P$ is the rate of energy delivery, $P = E / \Delta t$, where $\Delta t$ is the time.Therefore, $\Delta t = E / P = 960 \, W \cdot h / 120 \, W = 8 \, h$.Thus, the battery can deliver energy at the rate of $120 \, W$ for $8 \, h$.

$A$ battery with a $12 \, V$ emf has an initial charge of $80 \, A \cdot h$. If the potential across the terminals stays constant until the battery is completely discharged, then this battery can deliver energy at the rate of $120 \, W$ for a time of: (in $ \, h$)

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