A fully charged capacitor of capacity C is di | vedclass

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(B) The energy stored in a fully charged capacitor with capacitance $C$ and initial potential difference $V$ is given by $U = \frac{1}{2}CV^2$.Since t

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$\sqrt{\frac{2ms \Delta T}{C}}$

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(B) The energy stored in a fully charged capacitor with capacitance $C$ and initial potential difference $V$ is given by $U = \frac{1}{2}CV^2$.Since the capacitor is discharged through a resistance wire in a thermally isolated block,the entire electrical energy stored in the capacitor is converted into heat energy.The heat energy gained by the block is given by $Q = ms \Delta T$,where $m$ is the mass,$s$ is the specific heat,and $\Delta T$ is the rise in temperature.Equating the stored energy to the heat energy: $\frac{1}{2}CV^2 = ms \Delta T$.Solving for $V$: $V^2 = \frac{2ms \Delta T}{C}$.Therefore,$V = \sqrt{\frac{2ms \Delta T}{C}}$.

$A$ fully charged capacitor of capacity $C$ is discharged through a small resistance wire embedded in a solid block of specific heat $s$ and mass $m$ under thermally isolated conditions. If the temperature of the block is raised by $\Delta T$,the initial potential difference across the capacitor is

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