A carbonyl compound X (C_3H_6O) on oxidation | vedclass

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(C) The carbonyl compound $X$ has the molecular formula $C_3H_6O$. On oxidation,it gives a carboxylic acid $Y$ with the formula $C_3H_6O_2$. Since the

Vedclass · Accepted Answer

$CH_3-CH_2-CH=NOH$

Vedclass · Answer

(C) The carbonyl compound $X$ has the molecular formula $C_3H_6O$. On oxidation,it gives a carboxylic acid $Y$ with the formula $C_3H_6O_2$. Since the number of carbon atoms remains the same ($3$ carbons) during oxidation,$X$ must be an aldehyde (propanal,$CH_3-CH_2-CHO$). Ketones with $3$ carbons would undergo cleavage and produce acids with fewer carbon atoms. Therefore,$X$ is propanal $(CH_3-CH_2-CHO)$. The reaction of an aldehyde with hydroxylamine $(NH_2OH)$ forms an oxime: $CH_3-CH_2-CHO + NH_2OH \rightarrow CH_3-CH_2-CH=NOH + H_2O$. Thus,the oxime of $X$ is $CH_3-CH_2-CH=NOH$.

List-$I$	List-$II$
$A. \ C_6H_5NHNH_2$	$I. \ \text{Schiff base}$
$B. \ NH_2OH$	$II. \ \text{Hydrazone}$
$C. \ C_6H_5NH_2$	$III. \ \text{Oxime}$
	$IV. \ \text{Phenyl hydrazone}$

$A$ carbonyl compound $X$ $(C_3H_6O)$ on oxidation gives a carboxylic acid $Y$ $(C_3H_6O_2)$. The oxime of $X$ is:

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Match the following reagents with the products obtained when they react with a ketone.
List-$I$ List-$II$
$A. \ C_6H_5NHNH_2$ $I. \ \text{Schiff base}$
$B. \ NH_2OH$ $II. \ \text{Hydrazone}$
$C. \ C_6H_5NH_2$ $III. \ \text{Oxime}$
$IV. \ \text{Phenyl hydrazone}$

Correct answer is:

Identify the product $Y$ in the following reaction: $CH_3-CH=CH-CH_2-CHO + H_2 \xrightarrow{Ni} Y$

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