$\lambda_{1}$ and $\lambda_{2}$ are used to illuminate the slits. $\beta_{1}$ and $\beta_{2}$ are the corresponding fringe widths. The wavelength $\lambda_{1}$ can produce photoelectric effect when incident on a metal. But the wavelength $\lambda_{2}$ cannot produce photoelectric effect. The correct relation between $\beta_{1}$ and $\beta_{2}$ is

  • A
    $\beta_{1} < \beta_{2}$
  • B
    $\beta_{1} = \beta_{2}$
  • C
    $\beta_{1} > \beta_{2}$
  • D
    $\beta_{1} \geq \beta_{2}$

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