A_{(g)} xrightarrow{Delta} P_{(g)} + Q_{(g)} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given,half-life $t_{1/2} = 69.3 \ s$.For a first-order reaction,the rate constant $k = \frac{0.693}{t_{1/2}} = \frac{0.693}{69.3} = 10^{-2} \ s^{-

Vedclass · Accepted Answer

$1.12$

Vedclass · Answer

(B) Given,half-life $t_{1/2} = 69.3 \ s$.For a first-order reaction,the rate constant $k = \frac{0.693}{t_{1/2}} = \frac{0.693}{69.3} = 10^{-2} \ s^{-1}$.For first-order kinetics,$k = \frac{2.303}{t} \log \frac{P_0}{P_t}$,where $P_0$ is initial pressure and $P_t$ is pressure at time $t$.$10^{-2} = \frac{2.303}{230} \log \frac{0.4}{P_t}$.$1 = \log \frac{0.4}{P_t} \implies \frac{0.4}{P_t} = 10 \implies P_t = 0.04 \ atm$.From the reaction $A_{(g)} \rightarrow P_{(g)} + Q_{(g)} + R_{(g)}$:At $t = 0$,$P_A = 0.4 \ atm$,$P_P = 0, P_Q = 0, P_R = 0$.At $t = 230 \ s$,$P_A = 0.04 \ atm$. The decrease in pressure of $A$ is $0.4 - 0.04 = 0.36 \ atm$.According to stoichiometry,the pressure of products formed is $P_P = 0.36 \ atm, P_Q = 0.36 \ atm, P_R = 0.36 \ atm$.Total pressure $P_{total} = P_A + P_P + P_Q + P_R = 0.04 + 0.36 + 0.36 + 0.36 = 1.12 \ atm$.

Similar Questions

At $27^{\circ} C$ temperature,the time required for $75 \%$ completion of a first order reaction is $20 \ s$. What will be its rate constant?

The rate constant for the decomposition of $H_2O_2$ is $3.66 \times 10^{-3} \ s^{-1}$. If the initial concentration of $H_2O_2$ is $0.882 \ M$,then in how many seconds will its concentration become $0.600 \ M$?

$N_2O_{(g)} \to N_{2(g)} + \frac{1}{2}O_{2(g)}$
In a closed vessel,the reaction follows first-order kinetics. If starting with pure $N_2O_{(g)}$,the total pressure after time $t$ is $P_t$ and after a very long time is $P_{\infty}$,then which of the following expressions is correct?

Initial concentration of reactant in a first order reaction is $0.08 \text{ mol dm}^{-3}$. What concentration would remain after $40 \text{ minutes}$? (Given $\frac{[A]_0}{[A]_t} = 5.00$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module