^{15}N labeled E. coli is allowed to grow in | vedclass

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(C) The correct answer is $C$. According to the semi-conservative model of $DNA$ replication demonstrated by Meselson and Stahl,the parental $DNA$ str

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different density but do not resemble their parent $DNA$.

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(C) The correct answer is $C$. According to the semi-conservative model of $DNA$ replication demonstrated by Meselson and Stahl,the parental $DNA$ strands (labeled with $^{15}N$) separate,and each acts as a template for the synthesis of a new strand using $^{14}N$ from the medium. In the first generation,each $DNA$ molecule consists of one heavy strand $(^{15}N)$ and one light strand $(^{14}N)$. Since the two strands have different densities (one heavy and one light),the resulting $DNA$ molecule is a hybrid. Because the hybrid $DNA$ contains one $^{14}N$ strand,it does not resemble the original parent $DNA$ (which was entirely $^{15}N$).

$^{15}N$ labeled $E. coli$ is allowed to grow in a $^{14}N$ medium. The two strands of the $DNA$ molecule of the first generation bacteria have:

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