A mixture of CaCl_{2} and NaCl weighing 4.44 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical reactions involved are:$CaCl_{2} + Na_{2}CO_{3} \rightarrow CaCO_{3} + 2NaCl$$CaCO_{3} \xrightarrow{\Delta} CaO + CO_{2}$From the sto

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(A) The chemical reactions involved are:$CaCl_{2} + Na_{2}CO_{3} ightarrow CaCO_{3} + 2NaCl$$CaCO_{3} \xrightarrow{\Delta} CaO + CO_{2}$From the stoichiometry,$1 \ mol$ of $CaO$ is obtained from $1 \ mol$ of $CaCO_{3}$,which in turn comes from $1 \ mol$ of $CaCl_{2}$.Molar mass of $CaO = 40 + 16 = 56 \ g/mol$.Moles of $CaO = \frac{0.56 \ g}{56 \ g/mol} = 0.01 \ mol$.Therefore,moles of $CaCl_{2} = 0.01 \ mol$.Molar mass of $CaCl_{2} = 40 + (2 	imes 35.5) = 111 \ g/mol$.Mass of $CaCl_{2} = 0.01 \ mol 	imes 111 \ g/mol = 1.11 \ g$.Mass of $NaCl$ in the mixture $= 4.44 \ g - 1.11 \ g = 3.33 \ g$.Percentage of $NaCl = \frac{3.33 \ g}{4.44 \ g} 	imes 100 = 75 \%$.

Similar Questions

At $STP$,the volume of $4.4 \, g$ of an unknown gas is $2.24 \, L$. Which of the following is this gas?

The molecular weight of a gas is $45$. Its density at $STP$ is

How many moles of potassium chlorate need to be heated to produce $5.6 \, L$ of oxygen at $STP$?

$5.75 \ mg$ of sodium vapour is converted to sodium ion. If the ionisation energy of sodium is $490 \ kJ \ mol^{-1}$ and atomic weight is $23 \ g \ mol^{-1}$,the amount of energy needed for this conversion will be (in $kJ$)

What is produced when $1 \ mol$ of calcium phosphide reacts with excess water?
$(Hint: Ca_3P_2 + H_2O (excess) \rightarrow Ca(OH)_2 + 2PH_3)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module