A mixture of CaCl_2 and NaCl weighing 4.44 g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical reactions involved are:$CaCl_2 + Na_2CO_3 \rightarrow CaCO_3 + 2NaCl$$CaCO_3 \xrightarrow{\Delta} CaO + CO_2$From the stoichiometry,$

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(A) The chemical reactions involved are:$CaCl_2 + Na_2CO_3 ightarrow CaCO_3 + 2NaCl$$CaCO_3 \xrightarrow{\Delta} CaO + CO_2$From the stoichiometry,$1 \ mol$ of $CaO$ is obtained from $1 \ mol$ of $CaCO_3$,which in turn comes from $1 \ mol$ of $CaCl_2$.Molar mass of $CaO = 40 + 16 = 56 \ g/mol$.Molar mass of $CaCl_2 = 40 + 2 	imes 35.5 = 111 \ g/mol$.Given mass of $CaO = 0.56 \ g$,which is $0.56 / 56 = 0.01 \ mol$.Therefore,moles of $CaCl_2 = 0.01 \ mol$.Mass of $CaCl_2 = 0.01 	imes 111 = 1.11 \ g$.Mass of $NaCl$ in the mixture = Total mass - Mass of $CaCl_2 = 4.44 \ g - 1.11 \ g = 3.33 \ g$.Percentage of $NaCl = (3.33 / 4.44) 	imes 100 = 75\%$.

Similar Questions

$250 \ mL$ of a sodium carbonate solution contains $2.65 \ g$ of $Na_2CO_3$. If $10 \ mL$ of this solution is diluted to $1 \ L$,what is the concentration of the resultant solution (in $M$)?

The number of molecules of $CO_2$ liberated by the complete combustion of $0.1 \ mol$ of graphite in air is

$1 \ L$ of $N_2$ and $\frac{7}{8} \ L$ of $O_2$ gases are mixed at the same temperature and pressure. What is the relationship between their masses in the mixture?

At $STP$,'$x$' $g$ of a metal hydrogen carbonate $(MHCO_3)$ (molar mass $84 \ g \ mol^{-1}$) on heating gives $CO_2$,which can completely react with $0.2 \ mol$ of $MOH$ (molar mass $40 \ g \ mol^{-1}$) to give $MHCO_3$. The value of '$x$' is

White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of $HCl$ obtained by the hydrolysis of the product formed by the reaction of $62 \ g$ of white phosphorus with chlorine in the presence of water.

Vedclass Test Series

Exam Paper Generator

Online Exam Module