10 text{ g} of a mixture of BaO and CaO requi | vedclass

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(C) Let the mass of $CaO$ be $x 	ext{ g}$. Then the mass of $BaO$ is $(10 - x) 	ext{ g}$.Moles of $HCl = 	ext{Molarity} 	imes 	ext{Volume in L} =

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$52.6$

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(C) Let the mass of $CaO$ be $x 	ext{ g}$. Then the mass of $BaO$ is $(10 - x) 	ext{ g}$.Moles of $HCl = 	ext{Molarity} 	imes 	ext{Volume in L} = 2.5 	imes 0.1 = 0.25 	ext{ mol}$.The reactions are:$CaO + 2HCl ightarrow CaCl_2 + H_2O$$BaO + 2HCl ightarrow BaCl_2 + H_2O$Total moles of $HCl = 2 	imes (	ext{moles of } CaO) + 2 	imes (	ext{moles of } BaO)$$0.25 = 2 	imes (\frac{x}{56} + \frac{10 - x}{153})$$0.125 = \frac{153x + 560 - 56x}{56 	imes 153}$$0.125 	imes 8568 = 97x + 560$$1071 = 97x + 560$$97x = 511$$x = 5.268 	ext{ g}$Percentage of $CaO = \frac{5.268}{10} 	imes 100 = 52.68 \% \approx 52.6 \%$.

$10 \text{ g}$ of a mixture of $BaO$ and $CaO$ requires $100 \text{ cm}^3$ of $2.5 \text{ M } HCl$ to react completely. The percentage of calcium oxide in the mixture is approximately (Given: molar mass of $BaO = 153 \text{ g/mol}$,$CaO = 56 \text{ g/mol}$).

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