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(D) The circuit acts as a half-wave rectifier with a capacitor filter. When the $AC$ supply is connected, the $p-n$ junction diode conducts only durin

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$220 \sqrt{2} \,V$

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(D) The circuit acts as a half-wave rectifier with a capacitor filter. When the $AC$ supply is connected, the $p-n$ junction diode conducts only during the positive half-cycle (forward biased condition). During this cycle, the capacitor charges to the peak value of the input $AC$ voltage. Once charged, the capacitor maintains this peak voltage as there is no discharge path provided in the circuit. The potential difference $V$ across the capacitor is equal to the peak value of the input $AC$ voltage $(V_0)$. Given that the $RMS$ voltage $V_{	ext{rms}} = 220 \,V$, the peak voltage is calculated as: $V = V_0 = V_{	ext{rms}} 	imes \sqrt{2}$ $V = 220 	imes \sqrt{2} \,V = 220 \sqrt{2} \,V$.

$A$ $220 \,V$ $AC$ supply is connected between points $A$ and $B$ as shown in the figure. What will be the potential difference $V$ across the capacitor?

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