A convex lens has power P. It is cut into two | vedclass

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(D) $1$. When a lens is cut along its principal axis,the focal length of each half remains the same as the original lens,so the power of each half rem

Vedclass · Accepted Answer

Power of $L_1$ is $\frac{P}{2}$

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(D) $1$. When a lens is cut along its principal axis,the focal length of each half remains the same as the original lens,so the power of each half remains $P$. Thus,the power of $L_1$ is $P$.$2$. When a lens is cut perpendicular to its principal axis,the focal length of each part doubles,which means the power of each part becomes half of the original power.$3$. Since $L_2$ and $L_3$ are obtained by cutting the upper half of the original lens perpendicular to the principal axis,the power of $L_2$ is $\frac{P}{2}$ and the power of $L_3$ is $\frac{P}{2}$.$4$. Comparing these with the given options,the incorrect statement is that the power of $L_1$ is $\frac{P}{2}$.

$A$ convex lens has power $P$. It is cut into two halves along its principal axis. Further,one piece (out of two halves) is cut into two halves perpendicular to the principal axis as shown in the figure. Choose the incorrect option for the reported lens pieces.

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