A nuclear reactor delivers a power of 10^9 ,W | vedclass

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(D) Given, power delivered by the nuclear reactor, $P = 10^9 \,W$. Time, $t = 1 \,h = 3600 \,s$. Speed of light, $c = 3 	imes 10^8 \,m/s$. Using the

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$0.04$

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(D) Given, power delivered by the nuclear reactor, $P = 10^9 \,W$. Time, $t = 1 \,h = 3600 \,s$. Speed of light, $c = 3 	imes 10^8 \,m/s$. Using the mass-energy equivalence relation $E = mc^2$, the energy produced is $E = Pt$. Equating the two, we get $Pt = mc^2$. Rearranging for mass $m$, we have $m = \frac{Pt}{c^2}$. Substituting the values: $m = \frac{10^9 	imes 3600}{(3 	imes 10^8)^2} = \frac{3600 	imes 10^9}{9 	imes 10^{16}} = 400 	imes 10^{-7} \,kg = 4 	imes 10^{-5} \,kg$. Converting to grams: $m = 4 	imes 10^{-5} 	imes 10^3 \,g = 0.04 \,g$.

$A$ nuclear reactor delivers a power of $10^9 \,W$. The amount of fuel consumed by the reactor in one hour is: (in $\,g$)

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