A block kept on a rough surface starts slidin | vedclass

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(C) When a block is placed on an inclined plane,the forces acting on it are the gravitational force $mg$ (acting downwards),the normal force $N$ (perp

Vedclass · Accepted Answer

$	an 	heta$

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(C) When a block is placed on an inclined plane,the forces acting on it are the gravitational force $mg$ (acting downwards),the normal force $N$ (perpendicular to the surface),and the static friction force $f_s$ (acting up the incline).For the block to be in equilibrium,$N = mg \cos 	heta$ and $f_s = mg \sin 	heta$.The block starts sliding when the static friction reaches its limiting value,$f_s = \mu_s N$.Substituting the expressions for $f_s$ and $N$,we get $mg \sin 	heta = \mu_s (mg \cos 	heta)$.Dividing both sides by $mg \cos 	heta$,we obtain $\mu_s = \frac{\sin 	heta}{\cos 	heta} = 	an 	heta$.Thus,the coefficient of static friction is $	an 	heta$.

$A$ block kept on a rough surface starts sliding when the inclination of the surface is $\theta$ with respect to the horizontal. The coefficient of static friction between the block and the surface is

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